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SQL Server 2012 Hosting Spain - HostForLIFE.eu :: How to to check Recovery Model of a database in SQL Server ?

clock January 13, 2015 06:34 by author Peter

A Recovery Model is property of a database that control how transaction log is maintained. SQL Server supports simple, FULL and BULK-LOGGED recovery models. There are multiple ways in which to check recovery model of a database in SQL Server.

1. Using SQL Server Management Studio:
Right click on database in Object explorer -> Go to Properties dialog box -> Options page -> Recovery model

2. Using Metadata function – DATABASEPROPERTYEX():
SELECT [RecoveryModel] = DATABASEPROPERTYEX('SqlAndMe','Recovery')
GO 


Result Set: 
RecoveryModel
SIMPLE 

3. Using catalog view – sys.databases:
SELECT [DatabaseName] = name,
       [RecoveryModel] = recovery_model_desc
FROM   sys.databases
GO  


Result Set:
DatabaseName   RecoveryModel
master         SIMPLE
tempdb         SIMPLE
model          FULL
msdb           SIMPLE
Pubs           SIMPLE
EuWindows      SIMPLE
TestDB         SIMPLE
ProductCatalog SIMPLE
ReportDemo     SIMPLE
ReportServer   FULL
ReportServerTempDB  SIMPLE

(11 row(s) affected)

Using sys.databases catalog view is easier as it returns information of all databases on server. Hope this tutorial works for you!

 



SQL Server 2012 Hosting UK - HostForLIFE.eu :: Number of words in a string on SQL Server

clock January 9, 2015 06:01 by author Peter

In SQL Server there is not any inherent capacity accessible for discovering the number of words in a String. Here I reveal to both of you diverse methodologies for doing this, the first is the most simpleone, and is applicable only of these words are separated by a single space.

DECLARE @String VARCHAR(4000)
SELECT @String = 'SQL Server 2005'
SELECT LEN(@String) - LEN(REPLACE(@String, ' ', '')) + 1

As I said prior, the above query will provides for you the right result, just if the words are differentiated with a solitary space. Presently on the off chance that they are differentiated by more than one space, this will provide for you off base results as the results are basically relied on upon  Length of the original string. Along these lines, what will be the arrangement, simply compose a function  to do this.

CREATE FUNCTION dbo.udfWordCount(
@OriginalText VARCHAR(8000)
)
RETURNS int
as
/*
SELECT dbo.udfWordCount ('hello   world')
*/
BEGIN
    DECLARE @i int ,@j INT, @Words int
    SELECT     @i = 1, @Words = 0
    WHILE @i <= DATALENGTH(@OriginalText)
    BEGIN
        SELECT    @j = CHARINDEX(' ', @OriginalText, @i)
       if @j = 0
        BEGIN
            SELECT    @j = DATALENGTH(@OriginalText) + 1
        END
        IF SUBSTRING(@OriginalText, @i, @j - @i) <>' '
              SELECT @Words = @Words +1
        SELECT    @i = @j +1
    END
    RETURN(@Words)
END
GO
SELECT dbo.udfWordCount ('SQL Server2012')
SELECT dbo.udfWordCount ('SQL Server 2012 ')

 



SQL Server 2012 Hosting UK - HostForLIFE.eu :: Remove the Special Characters in a String

clock December 16, 2014 07:30 by author Peter

Today, I am going to tell you how to replace the special characters in a string with spaces. In this case, I need to use PATINDEX.

PATINDEX
It will returns the starting position of the first occurrence of a pattern in a specified expression, or zeros if the pattern is not found, on all valid text and character data types. And this is the code that I used:
PATINDEX ( '%pattern%' , expression )

Example:
DECLARE @Str varchar(100)
SET @Str='Welcome!@+to+#$%SQL+^&*(SERVER)_+'
SELECT PATINDEX('%SQL%', @Str)


Here is the result from that code:

Remove Special Characters from String in SQL Server DECLARE @regexp INT
DECLARE @Str varchar(100)
SET @Str='Welcome!@+to+#$%SQL+^&*(SERVER)_+   '
SET @regexp = PATINDEX('%[^a-zA-Z0-9 ]%', @Str)
WHILE @regexp > 0
BEGIN
SET @Str = STUFF(@Str, @regexp, 1, ' ' )
SET @regexp = PATINDEX('%[^a-zA-Z0-9 ]%', @Str)
Print @regexp
END
SELECT @Str


Result
:

STUFF
This STUFF function inserts a string into another string. It deletes a specified length of characters in the first string at the start position and then inserts the second string into the first string at the start position. This is the code:
STUFF ( character_expression , start , length , replaceWith_expression )


Example:
DECLARE @regexp INT
DECLARE @Str varchar(100)
SET @Str='welcome to sql server'
SET @Str = STUFF(@Str, 1, 1, '@' )
Select @str 



SQL Server 2012 Hosting UK - HostForLIFE.eu :: Moving a Table to Another Schema

clock November 20, 2014 05:35 by author Peter

From SQL Server 2005, all tables are grouped into schemas. Even though making a table in case the schema name isn't specified it's developed inside the default schema from the user making it. You are able to use ALTER SCHEMA command to move tables in among schemas. For instance, in case I develop a table using below script it is going to be developed below my default schema that is dbo:
USE [hostsql]
GO
CREATE TABLE Employee
(
       ID     INT,
       Name VARCHAR(20)
)
GO
SELECT name, [schema] = SCHEMA_NAME(schema_id)
FROM   sys.tables
WHERE  name = 'Employee'
GO

Result Set:
name            schema
Employee      dbo
(1 row(s) affected)

As you are able to notice coming from the output the table is currently in dbo schema. Currently to move this table to another schema utilizing ALTER SCHEMA command, first we have to create the schema in case it doesn't exist by now. When that many of us can move table to new schema.
USE [SqlAndMe]
GO CREATE SCHEMA Staff
GO 
ALTER SCHEMA Staff
TRANSFER dbo.Employee
GO 
SELECT name, [schema] = SCHEMA_NAME(schema_id)
FROM   sys.tables
WHERE  name = 'Employee'
GO


Result Set:
name            schema
Employee      Staff 
(1 row(s) affected)

As you can see from the result, the table of Employee is now moved to Staff schema.



SQL Server 2012 Hosting - HostForLIFE.eu :: How to fix Error: The specified instance of SQL Server is hosted by a system that is not a Windows Server Failover Cluster(WSFC) node

clock October 30, 2014 08:43 by author Peter

Today, I will write about How to fix Error:  “The specified instance of SQL Server is hosted by a system that is not a Windows Server Failover Cluster(WSFC) node" on SQL Server 2012. And this is the error message:

The specified instance of SQL Server is hosted by a system that is not a Windows Server Failover Cluster(WSFC) node. (Microsoft.SqlServer.Management.HadrTasks)

The local node is not part of quorum and is therefore unable to process this operation. This may be due to one of the following reasons:

  • The local node is not able to communicate with the WSFC cluster.
  • No quorum set across the WSFC cluster.

The local node isn’t part of quorum and so unable to process that operation.This prompt me that perhaps the second instance doesn't understand itself its HADR enable. thus I qery sys.dm_hadr_cluster_members and sys.dm_hadr_cluster for both nodes.

On node1, it will come correct information. On node2, the result's empty.
SELECT *
FROM sys.dm_hadr_cluster_members;
Go
select * from sys.dm_hadr_cluster

The way to fix it's disable the HADR from SQL Server configuration manager . Bounce SQL Server and SQL agent. rentable HADR and bounce SQL server and SQL agent. The issue was resolved after second bounce

.



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